Question 51235
Let L = number of loaves of bread.
C = total cost of the loaves.

Machine cost:
C = 199 + .79L


Store cost:
C = 1.59L


199 +.79L = 1.59L


Subtract .79L from each side:
199+.79L -.79L = 1.59L - .79L
199=.8L


Divide both sides by .8:
{{{199/.8=(.8L)/.8 }}}
{{{159.2 = L}}}


Answer:  On the 160th loaf of bread, the machine becomes the lesser cost.


R^2 at SCC