Question 510149
Factor:
{{{64c^2+81-144c}}} Rewrite in standard form:
{{{64c^2-144c+81}}} Notice that the first and last terms are perfect squares: {{{64 = 8^2}}} and {{{81 = 9^2}}} so try...
{{{(8c-9)(8c-9)}}}  Check by multiplying these factors to see that you get the original trinomial.