Question 51207
This is a parabola that opens upward, and the axis of symmetry for such a graph in the form of {{{y=ax^2+bx+c}}} will always be {{{x=-b/(2a)}}}.


In the case of {{{y=x^2+6x +5}}}, the axis of symmetry will be {{{x=-6/2=-3}}}


The graph looks like this, using a graphing calculator, or this fantastic "algebra.com" calculator:
{{{graph(300,300,-10,10,-10,10, x^2+6x+5) }}}


R^2 at SCC