Question 51226
Anytime you have a fraction equal to a fraction, like this:{{{5/(2x-3) = 3/(x-5)}}}, remember that 


{{{a/b=c/d}}} means that {{{a*d=b*c}}}


{{{5/(2x-3) = 3/(x-5)}}} means that {{{5*(x-5) =3(2x-3)}}}


Now, 5x-25 =6x - 9


Subtract 5x from each side to get all the x terms on the right side:
5x-5x -25= 6x-5x-9
-25 = x-9


Next, add +9 to each side:
-25+9 = x-9+9
-16=x


Check by substituting back into the original equation:
{{{5/(2x-3) = 3/(x-5)}}}
{{{5/(-32-3)= 3/(-16-5)}}}
{{{5/(-35)=3/(-21)}}}
{{{1/(-7)= 1/(-7)}}}  It checks!!


R^2 at SCC