<PRE><B>Question 506675</B>
Let
1st  Interger = x+2
2nd   Interger = x+4
3rd t  Interger = x+6
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Given
4(x+2)-(x+6)=2(x+4)+6
4x+8-x-6=2x+8+6
3x+2=2x+14
3x-2x=14-2
x=12
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1st  Interger = x+2 =12+2 =14
2nd   Interger = x+4=12+4=16
3rd t  Interger = x+6=12+6=18
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Check
4(x+2)-(x+6)=2(x+4)+6
4(14)-18=2(16)+6
56-18=32+6
38=38
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