Question 509098
I have a mixture problem to find 15 milliliters of a solution that is 2% active ingredient and I have a 10% and 1% solution in my stock. 
How do i get 2% solution?
:
let x = amt of 10% solution
The resulting amt is to be 15 ml, therefore
(15-x) = amt of 1% solution
:
.10x + .01(15-x) = .02(15)
.10x + .15 - .01x = .3
.10x - .01x = .3 - .15
.09x = .15
x = {{{.15/.09}}}
x = 1{{{2/3}}} ml of 10% solution
and 
15 - 1{{{2/3}}} = 13{{{1/3}}} ml of 1% solution