Question 509149
Given that Y varies inversely as the cube root of X-5 and Y = 3, X = 13 form an equation connecting X and Y.
----------
{{{y = k/root(3,(x-5))}}}
{{{3 = k/root(3,8) = k/2}}}
k = 6
--> {{{y = 6/root(3,(x-5))}}}
------------------
Hence find X when Y = 2
{{{2 = 6/root(3,(x-5))}}}
{{{root(3,(x-5)) = 3}}}
x-5 = 27
x = 32