Question 51152
its easy say x=2ab, y=a^2-b^2  z=a^2+b^2
and a, b are any kind of positve integers(whole numbers)

make x^2+y^2=z^2

for an example, let a=2, b=1
 
        so substitude the values
                    x^2+y^2=z^2  
               (2ab)^2+(a^2-b^2)^2=(a^2+b^2)^2
                (2*2*1)^2+ (2^2-1^2)^2= (2^2+1^2)^2
                      4^2 + 3^2  = 5^2
                      16  + 9    = 25


you can sustitute as much as U want