Question 509064
Trinomial factor of (x+y)^2-3x-3y+2
**
(x+y)^2-3x-3y+2
(x+y)^2-3(x+y)+2=0
let u=(x+y)
u^2-3u+2=0
(u-2)(u-1)=0
u=2 
or 
u=1
..
For u=2
x+y=2
y=-x+2
..
x+y=1
y=-x+1
..
ans:
Function is two parallel lines with same slope=-1, but with different y-intercepts (1, and 2)