Question 509035

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(1,28\right)]. So this means that {{{x[1]=1}}} and {{{y[1]=28}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(3,40\right)].  So this means that {{{x[2]=3}}} and {{{y[2]=40}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(40-28)/(3-1)}}} Plug in {{{y[2]=40}}}, {{{y[1]=28}}}, {{{x[2]=3}}}, and {{{x[1]=1}}}



{{{m=(12)/(3-1)}}} Subtract {{{28}}} from {{{40}}} to get {{{12}}}



{{{m=(12)/(2)}}} Subtract {{{1}}} from {{{3}}} to get {{{2}}}



{{{m=6}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(1,28\right)] and *[Tex \LARGE \left(3,40\right)] is {{{m=6}}}