<PRE><B>Question 508963</B>
Let
1st  Interger = x+2
2nd  Integer = x+4
3rd  Integer = x+6
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Given
5(x+2)+6(x+4)+7(x+6)=148
5x+10+6x+24+7x+42=148
18x+76=148
18x=148-76
18x=72
18x/18=72/18
x=4
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1st  Integer = x+2 =4+2=6
2nd  Integer = x+4 = 4+4=8
3rd  Integer = x+6 = 4+6=10
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Check
(5*6)+6*(8)+7*(10)=148
30+48+70=148
148=148
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