Question 508955

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5 T, H 2 U 


5 0, H 2 U Thousands place can ONLY be 0 or 1. 


Thousands place = 0
5 0, H 2 U. This means that H (hundreds) + U (units) = 16 [23 – (5 + 2)]. We therefore have 8 & 8, 9 & 7, or 7 & 9. this equates to 3 possibilities, which are:


50,828
50,927
50,729


Thousands place = 1
5 1, H 2 U. This means that H (hundreds) + U (units) = 15 [23 – (5 + 1 + 2)]. We therefore have 6 & 9, 9 & 6, 7 & 8, 8 & 7. This equates to 4 possibilities, which are:


51,629
51,926
51,728
51,827.


As seen, only 7 possibilities exist.


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