Question 508970
Assuming you problem is:
{{{ (2x^3-x^2-6x)/(2x^2-7x+6)}}}
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simplify the numerator
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{{{2x^3-x^2-6x = x(2x^2-x-6)}}}
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{{{x(2x^2-x-6) = x(2x+3)(x-2)}}}
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simplify the denominator
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{{{ 2x^2 -7x +6 = (2x-3)(x-2) }}}
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reform the division
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{{{ ( x(2x+3)(x-2) ) / ( (2x-3)(x-2) ) }}}
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the (x-2) terms will cancel
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{{{(x(2x+3)) / ((2x-3))}}}
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x = 0, x = -3/2