Question 508812
write an equation in slope intercept form which is perpendicular to the line y= -3x+0, and goes through the midpoint (-1/2, 3/2).
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The slope of y = -3x is -3
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The slope you want is 1/3
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Form: y = mx+b
3/2 = (1/3)(-1/2) + b
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3/2 = (-1/6) + b
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9/6 = (-1/6) + b
b = 10/6
b = 5/3
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Equation:
y = (1/3)x + (5/3)
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Cheers,
Stan H.
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