<PRE><B>Question 508793</B>
When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2 – 3y ? i cant remeber how to do these
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3x^2-2y = 3(3^2)-3(5) = 27-15 = 12
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2x^2 - 3y = 2(3)^2-3(5) = 18-15 = 3
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Ans: 12-3 = 9
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Cheers,
Stan H.</PRE>