Question 508764
Exactly 30 minutes after the Andersons' head south on the highway, the Quentins' set out from the same point and follow the same route. 
The Andersons' travel at 50 mi/h. 
The Quentins' travel at 65 mi/h. 
How long does it take the Quentins' to overtake the Andersons'?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Anderson DATA:
rate = 50 mph ; time = t hrs ; distance = r*t = 50t miles
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Quentin DATA:
rate = 65 mph ; time = t-(1/2) hrs ; distance = r*t = 65t-65/2 miles
-------------------
 Equation:
distance = distance 
50t = 65t-(65/2)
15t = (65/2)
time = 2 hrs 10 minutes (time for the Quentins to overtake the Andersons)
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Cheers,
Stan H.
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