Question 508575
normally distributed with a mean of 73 and a standard deviation of 8.
1. What is the probability of getting between a 60 and 70 on this exam? 
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z(60) = (60-73)/8 = -13/8 = -1.6250
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z(70) = (70-73)/8 = -3/8 = -0.375
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Using my TI-84 I get: 
P(60< x <70) = P(-1.625< z <-0.375) 
= normalcdf(-1.625,-0.375) 
= 0.3017
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Cheers,
Stan H.
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