Question 508543
Basically, this question is asking  a^-6 = 1/3 for what value of a satisfies this equation?

Well, to solve this we must *undo* a^-6 by raising it to the -1/6 power.

(a^-6)^(-1/6)  =  (1/3)^(-1/6) =  1.20 <---- Answer


To check,   we put in  log(1/3) / log(1.2)  [change of base formula] and we get roughly -6, since we rounded our base to 1.20.

Thus a = 1.20

Hopefully this helped!

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