Question 51090
x to the 2nd power -5x+4
x^2-5x+4 [Factor]
(x-4)(x-1)
(x-4)(x-1) [Set each factor equal to zero]
.
x-4=0 [Solve for x]
x=4
.
x-1=0 [Solve for x]
x=1
.
So, the solution set is {4, 1}