Question 51072
The height h, in feet, of a baseball above the ground t seconds after it is hit is given by h = -16^2 + 52t + 4.5. Use this equation to determine the number of seconds, to the nearest 0.1 second, from the time the ball is hit until the ball hits the ground.
APART FROM START WHEN H=0 AT T=0.
WHEN IT HITS THE GROUND AGAIN H=0
SO WE HAVE TO FIND T FOR THIS CASE
16T^2-52T-4.5=0
T=[52+SQRT{52^2-4(16)(-4.5)]/(2*16)=3.33 SEC=3.3 SEC