Question 507617
Let the consecutive odd integers = {{{ n }}} and {{{ n+2 }}}
( this could be 3 and 5 or 17 and 19 )
If the sides of a rectangle are {{{a}}} and {{{b}}}, then perimeter
{{{ P = 2a + 2b }}}
In this case,
{{{ P = 2n + 2*(n + 2) }}}
{{{ 120 = 2n + 2n + 4 }}}
{{{ 4n = 116 }}}
{{{ n = 29 }}}
{{{ n + 2 = 31 }}}
Area = {{{ 29*31 = 899 }}}
check:
{{{ P = 2n + 2*(n + 2) }}}
{{{ P = 2*29 + 2*31 }}}
{{{ P = 58 + 62 }}}
{{{ P = 120 }}}
OK