Question 507400
e^ (x+6)= e^(x) + 1 
Solve for x
e^ (x+6)- e^(x) = 1
e^x(e^6)-e^x=1
(e^x)(e^6-1)=1
take ln of both sides
ln(e^x)+ln(e^6-1)=ln(1)
x+ln(e^6-1)=0
x=-ln(e^6-1)
x=-5.9975