Question 507520
log(3x+4)=2log(x) 
log(3x+4)=log(x^2) 
3x+4 = x^2 
0 = x^2 - 3x - 4
0 = (x-4)(x+1)
x = {4, -1}
we can throw out the -1 solution (extraneous) leaving:
x = 4