<PRE><B>Question 507315</B>
How many quarts of water [0% alcohol] need to be added to 50 quarts of 80% alcohol to obtain a 10% alcohol solution?
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let x=quarts of water to be added
80%*50+0%x=10%(50+x)
40+0=5+.1x
40-5=.1x
35=.1x
x=350 quarts
ans:
350 quarts of water need to be added to 50 quarts of 80% alcohol to obtain a 10% alcohol solution?</PRE>