<PRE><B>Question 507315</B>
How many quarts of water [0% alcohol] need to be added to 50 quarts of 80% alcohol to obtain a 10% alcohol solution?
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Equation:
water + water = water
x + 0.20*50 = 0.90(x+50)
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Multiply thru by 100 to get:
100x + 20*50 = 90x + 90*50
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10x = 70*50
x = 350 quarts (amt. of water needed)
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Cheers,
Stan H.</PRE>