Question 506870
Let w be the width
length= w+2
Area=w(w+2)

Perimeter=2(w)+2(w+2)-8

{{{(w+2)w=2(w)+2(w+2)-8}}}
{{{w^2+2w=2w+2w+4-8}}}
{{{w^2+2w=4w-4}}}
{{{w^2-2w+4=0}}}

Next solve using Quadratic Formula.