Question 506535
---------------percent	----------------			quantity								
Alcohol I	40	----------------			x	liters							
Alcohol II	65	----------------	20	-	x	liters							
Mixture	50.00%	----------------	20										
													
40x+65(	20	-	x	)	=	50	*	20	
													
40x	+	1300	-	65	x	=			1000			
40x	-	65	x			=	1000	-	1300			
-25	x			=	-300								
/	-25												
	x			=	12		liters			40.00%		Alcohol I	
					8		liters			65.00%		Alcohol II