Question 506537
	--------percent	----------------	quantity									
Hcl I	20	----------------			60	ml						
Hcl II	5	----------------			x	ml						
Mixture	10	----------------	60	+	x	ml						
												
20	*	60	+	5	x	=	10	(	60	+	x	)
1200	+	5	x	=	600	+	10	x				
5	x	+	-10	x	=	600	-	-1200				
-5	x	=	-600									
/	-5											
x	=	120										
		120	ml		of	5	%	Hcl II