Question 506392
You would let the integers be x, x+1, x+2, x+3 instead of x, x+2, x+4, x+6.


Their sum is 4x+6, and we set this less than or equal to 25:


*[tex \LARGE 4x + 6 \le 25]


*[tex \LARGE 4x \le 19 \Rightarrow x \le 4] (5 is too large)


The only pairs are (1,2,3,4),(2,3,4,5),(3,4,5,6), and (4,5,6,7).