Question 506190
1) We are going to call the unknown length of the pipe x so
Main Pipeline length= x
Length of 1 of the smaller pipelines = x+2.6

Total length= x+3(x+2.6)= 35.4 

distribute and solve for x

x+3x+7.8=35.4
4x+7.8=35.4
4x=27.6
x=6.9

The main pipeline's length is 6.9.

The length of the smaller pipes is x+2.6 so

6.9+2.6=9.5
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2) distance=speed*time
distance up the slope= speed(up)*time(up)
distance down the slope= speed(down)*time(down)
Because it is the same slope distance(up)=distance(down)
speed(up)*time(up)=speed(down)*time(down)

We are going to call the time it takes to go up the slope x so
Time (up)= x
Time (down)= 24-x

Plug in what we know and you have
50x=150(24-x)
Now distribute and solve
50x=3600-150x
200x=3600
x=18
Plug it into our original d=s*t and you get
d=50*18
d=900