Question 505920
I have to solve by graphing 7x- 3y = 1 and 2y = 5x.
Put both equations into the slope/intercept format
7x - 3y = 1
-3y = -7x + 1
Y has to be positive, multiply both sides by -1
3y = 7x - 1
divide both sides by 3
y = {{{7/3}}}x - {{{1/3}}}; the slope/intercept form (Red)
and
2y = 5x
divide both sides y 2
y = {{{5/2}}}x
y = 2.5x
:
Plot these equations from x=-3, to x=+1
y = {{{7/3}}}x - {{{1/3}}}
replace x with -3
y = {{{7/3}}}(-3) - {{{1/3}}}
y = -7 - {{{1/3}}}
y = -7{{{1/3}}} 
y = - 7.33
do the same for x = -2, x = 0, and x = +1
--------------
 x | y
--------
-3 |-7.333
-2 |-5
 0 |-.333
+1 |+2
:
Do the same for y = 2.5x (green)
 x | y
--------
-3 |-7.5
-2 |-5
 0 | 0
+1 |2.5
:
You should note that where x=-2, y = -5 in both equation so this is the solution
-2,-5, this should be the intersection of the graph
:
Graph this with these points, intersection is not easy to see but should look like this
{{{ graph( 300, 200, -4, 2, -7, 4, 2.33x-.333, 2.5x) }}}