Question 505933
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ x\ +\ 6\ =\ 0]


Use the quadratic formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}]


for your problem:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ 1\ \ ], *[tex \LARGE b\ =\ 1\ \ ], and *[tex \LARGE c\ =\ 6]


If the radicand is < 0 (and it will be in this problem), then put an *[tex \Large i] in front of the radical and change the radicand to positive.  That is to say if *[tex \Large x\ <\ 0], then 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{x}\ =\ i\sqrt{|x|}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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