<PRE><B>Question 505296</B>
A Rectangle is 4 times as long as it is wide. A second rectangle is 3 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centimeters greater than the first. What are the dimentions of the original rectangle?
**
original rectangle:
let x=width
4x=length
area=x*4x=4x^2
..
2nd rectangle
x+2=width
4x+3=length
area=(x+2)(4x+3)=4x^2+11x+6
..
original area+530=2nd area
4x^2+530=4x^2+11x+6
11x+6=530
11x=530-6=524
x=524/11=47.64 cm
4x=190.55 cm
ans:
dimensions of original rectangle:
width=47.64 cm
length=190.55 cm</PRE>