Question 505843
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Rob begins with R cents, Sam begins with S cents.
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Rob has twice as much as Sam. 
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R = 2S
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Then Sam gives Rob 1 quarter, 2 nickels, and 3 pennies.<pre>
(That's 38 cents)
Now Sam has S-38 cents, and Rob has R+38
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Rob then gives Sam 8 dimes.<pre>
(That's 80 cents)
Now Sam has S-38+80, and Rob has R+38-80.
Simplifying,
Now Sam has S+42 cents and Rob has R-42  
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...they both end up with the same amount.<pre> 
(set them equal)
So  S+42 = R-42
       S = R-84
So we have this system of equations to solve:
R = 2S
S = R-84
Solve that system by substitution and get 
R = 168 cents or $1.68, S = 84 cents.
Rob originally had $1.68
Edwin</pre>