Question 51028
OK, no problem...
Lets just take these one step at a time.
-2-4(2y-1)=(6-2y)3
What if we just work on one side of the equation at a time, that might help.
So all we have is the left side:
-2-4(2y-1)
If we follow the order of operations we know that we should work with the parenthesis first using the distributive property, forget about the -2 for now. 
So we have...
-4 X 2y and -4 X -1
this becomes -8y and -4 or -8y -4
ok so far?
now if we bring back the -2 we have...
-2 -8y -4 
Does this make sense?
Then we can combine like terms (the -2 and the -4)
-8y -6 
Ok?
Now we put that aside and work on the right side of the equation...
(6-2y)3 or we could look at this like 3(6-2y)
So now we have...
3 X 6 and 3 X -2y
this becomes 18 and -6y or 18 - 6y
ok so far?
now that we have re-written the equation lets bring it back together...
-8y -6 = 18 - 6y
does this make sense?
now we need to solve for y...
we can combine like terms again accross the equals sign.
In order to do that we can add 6 to both sides and we add 6y from both sides to make it look like this...
-8y - 6 + 6 + 6y = 18 + 6 - 6y + 6y
the 6's will cancel on the left side and the 6y's will cancel on the right.
-8y + 6y = 18 + 6 
now we can combine the terms...
-2y = 24
ok so far?
now to completely isolate the y variable we can divide both sides by -2...
{{{(-2y)/-2 = 24/-2}}}
the -2's cancel on the left side 
{{{y = 24/-2}}}
and we can reduce the right fraction to 
-12
so our final answer is...
y = -12
I hope this helps.
Please let me know if you have any more questions!
Good Luck.
Alan