Question 505105
What is the exact value of the tan of -75
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Use tan addition formula:tan(s+t)= (tan s+tan t)/(1-tan s tan t)
For given problem:
s=-45º
t=-30º
reference angle -75º in quadrant IV
tan(-75)=tan(-45-30)=(tan -45º+tan -30º)/(1-(tan -45º*tan -30º))
tan(-45º)=-1
tan(-30º)=-√3/3
tan(-75)=(-1-√3/3)/(1-(-1*-√3/3))
tan(-75)=-(1+√3/3)/(1-√3/3)