Question 505113
jet traveling at 564km/h leaves 1/2 hour ahead of jet traveling 744 km/h
going the same direction.
use an equation to find out how long the second jet will take to over take the first?
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Slower jet DATA:
rate = 564 km/hr ; time =  x hrs ; distance = rt = 564x km
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Faster jet DATA:
rate = 744 km/hr ; time = x-(1/2) hrs ; distance = rt = 744[x-(1/2)]
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Equation:
distance = distance
564x = 744x - 372
180x = 372
x = 2.0667 hrs
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Cheers,
Stan H.