Question 504967
If I call the day number {{{d}}}, then
when {{{ d = 1}}}, number of nickels is {{{ 0 + d^2 }}} = 1
when {{{ d = 2 }}}, number of nickels is {{{ 1 + d^2 }}} = 5
when {{{ d = 3 }}}, number of nickels is {{{ 5 + d^2 }}} = 14
when {{{ d = 4 }}}, number of nickels is {{{ 14 + d^2 }}} = 30
So, on any given day, {{{d}}}, she gets the number that she got
the number she got the previous day plus {{{ d^2 }}} more.
On the 10th day, she got
{{{10^2}}} + number on the previous day
On the 9th day, she got
{{{9^2}}} + number on previous day
On the 8th day, she got
{{{8^2}}} + number on previous day
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Notice this is
{{{ 10^2 + 9^2 + 8^2 + 7^2 + 6^2 + 5^2 + 4^2 + 3^2 + 2^2 + 1^2 }}}
{{{ 100 + 81 + 64 + 49 + 36 + 25 + 16 + 9 + 4 + 1 = 385}}}