Question 504157
Graph the solution set and write it in interval notation.
a. |x+4|>=7 
b.|7x+5|-4<3 
c.3x+3<2x+5 or x-2>3
**
a.|x+4|&#8805;7
x+4&#8805;7 
x&#8805;3
or
x+4&#8804;-7
x&#8804;-11
solution:
number line
<====-11]........[3====>
(-&#8734;,-11] U [3, &#8734;)
..
b. |7x+5|-4<3
7x+5-4<3
7x<2
x<2/7
and
-7x-5-4<3
-7x<12
divide by -7 and reverse inequality sigh
x>-12/7
solution:
(-12/7, 2/7)
number line
<.......(-12/7===2/7).........>
..
c.3x+3<2x+5 or x-2>3
x<2 or x>5
number line
<====2)........(5====>
solution:
(-&#8734;, 2) U (5, &#8734;)
..
symbols: 
"[" includes number
"(" does not include number