Question 504668
c(x+2)- 5 = b(x-3), solve for x 
:
cx + 2c - 5 = bx - 3b
:
perform the necessary operations to get the x's on the left
cx - bx = -3b - 2c + 5
;
Factor out x
x(c-b) = -3b - 2c + 5
:
Divide both sides by (c-b)
x = {{{((-3b-2c+5))/((c-b))}}}