Question 504355
factor this expression completely. 6x^2-27x-15
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Common Factor: 3
= 3[2x^2-9x-5)
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How to factor 2x^2-9x-5
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Think of 2 numbers whose product is 2*-5 = -10
and whose sum is -9
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The numbers are -10 and +1
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Replace -9 by -10+1
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2x^2-9x-5 can be written as
2x^2-10x+x-5
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Factor the 1st 2 and the last 2 terms separately:
2x(x-5) + (x-5)
Factor again to get:
(x-5)(2x+1)
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Final answer: 3(x-5)(2x+1)
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Cheers,
stan H.