Question 504033
To do the graphs, you need to get the equations in slope-intercept form:  y = mx+b.
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3x +2y = 6
2y = -3x +6
y = -3/2x +3
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x=0, y=3 defines the point (0,3)
x=2, y=0 defines the point (2,0)
now you can draw the first line
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I assume the second equation is:  y = -3/2x -1.
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It has the same slope as the first equation, so it will be parallel.
Since there is no intersection for parallel lines, there is no single point that solves them both.
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{{{graph(500,500,-5,5,-5,5,-3/2*x+3,-3/2*x-1)}}}