Question 504021

Let W= the width
Therefore, Length(L)= 2W-8 "8meters less than twice of W"
           Perimeter=470

Formula: the perimeter of a rectangle; P=2(L+W)

=> 470=2[(2W-8)+W)
   470=2(3W-8)
   470=6W-16
470+16=6w
   486=6W
 {{{486/6=W}}}
 W=81

However, L= (2*81)-8 =154meters

Verification:
Length=154
Width=81

Perimeter=2(154+81)=470meters