Question 504016


{{{4x+3y=2}}} Start with the given equation.



{{{3y=2-4x}}} Subtract {{{4x}}} from both sides.



{{{3y=-4x+2}}} Rearrange the terms.



{{{y=(-4x+2)/(3)}}} Divide both sides by {{{3}}} to isolate y.



{{{y=-(4/3)x+2/3}}} Break up the fraction.



So the equation {{{y=-(4/3)x+2/3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-4/3}}} and the y-intercept is {{{b=2/3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,\frac{2}{3}\right)]


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Thanks,


Jim