Question 503945
Call the pictures {{{a}}}, {{{b}}}, and {{{c}}}
The orderings are:
a b c
b c a
c a b
b a c 
a c b
c b a
there are 6 different ways to arrange he pictures
the way to calculate it is:
(3 possible in 1st position)x(2 left in 2nd position)x( 1 left for last position) = 6 different ways
You would need to calculate this way if there 
were 10 children:
{{{ 10*9*8*7*6*5*4*3*2*1 = 3628800 }}} possible orders