Question 503868
(y-9)/(y+5) = 1/7
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Cross-multiply to get:
7(y-9) = y+5
7y-63 = y+5
6y = 68
y = 11 1/3
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Check:
((34/3)-9)/((34/3)+5) = 1/7
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((34/3)-(27/3))/((34/3)+(15/3)] = 1/7
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(7/3)/(49/3) = 1/7
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7/49 = 1/7
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1/7 = 1/7
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Cheers,
Stan H.
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