Question 503746
{{{8a^3+12a^2+6a-b^3+9b^2-27b+28}}}
Use the formula
{{{a^3+3a^2b+3ab^2+b^3=(a+b)^3}}}
{{{a^3-3a^2b+3ab^2-b^3=(a-b)^3}}}
{{{8a^3+12a^2+6a-b^3+9b^2-27b+28=(2a)^3+3*(2a)^2*1+3*2a*1^2+1^3-(b^3-3*b^2*3+3*b*3^2-3^3)=(2a+1)^3-(b-3)^3}}}