Question 503737

{{{7/(x+2)-4/(2x-3)}}}



{{{(7(2x-3))/((x+2)(2x-3))-4/(2x-3)}}}



{{{(14x-21)/((x+2)(2x-3))-4/(2x-3)}}}



{{{(14x-21)/((x+2)(2x-3))-(4(x+2))/((x+2)(2x-3))}}}



{{{(14x-21)/((x+2)(2x-3))-(4x+8)/((x+2)(2x-3))}}}



{{{(14x-21-(4x+8))/((x+2)(2x-3))}}}



{{{(14x-21-4x-8)/((x+2)(2x-3))}}}



{{{(10x-29)/((x+2)(2x-3))}}}



{{{(10x-29)/(2x^2+x-6)}}}



So {{{7/(x+2)-4/(2x-3)}}} simplifies to {{{(10x-29)/(2x^2+x-6)}}}



In other words, {{{7/(x+2)-4/(2x-3) = (10x-29)/(2x^2+x-6)}}}



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Thanks,


Jim