Question 503708
A line perpendicular to y = 2x will have slope = -1/2.
y = -1/2x + b
We want it to go through (-7,2), so substitute these values to find 'b'.
2 = -1/2(-7) + b
2 = 7/2 + b
b = -3/2
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y = -1/2x -3/2
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1/2x + y = -3/2
x + 2y = -3 in standard form
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A line passing through (-2,3) and (6,1) can be determined.
m = change in y / change in x
change in y = 1-3 = -2
change in x = 6-(-2) = 8
m = -2/8 = -1/4
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y = -1/4x + b
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substitute a point you know, say (-2,3)
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3 = -1/4*-2 + b
3 = 1/2 + b
2 1/2=b
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y = -1/4x + 2 1/2
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1/4x + y = 5/2
x + 4y = 10 in standard form
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{{{graph(500,500,-15,15,-15,15,2*x,-1/2*x-3/2,-1/4*x+2.5)}}}
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It is better to post new questions than to add them to an existing question. But I'll give these a try.

1. -[2x-(5x+2)] = 2+(2x+7) 

HOW DO I DISTRIBUTE WITH THE NEGATIVE OUTSIDE?  WHAT DO THE BRACKETS MEAN?? 

The square brackets are just meant to be distinctive from parentheses.  In English we usually have square brackets to enclose parentheses, and curly braces to enclose square brackets.  You can replace them with parentheses.  But you should always work from the innermost parentheses out.
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Let u = 5x+2 to make is simpler.
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-(2x -u) = -2x -(-u) = -2x +u
So, replace the 'u' with what it means:
-2x + (5x+2)
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-(2x-(5x+2)) = 2+(2x+7)
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-2x +(5x+2) = 2 + (2x+7)
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-2x +5x +2 = 2 + 2x + 7
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3x + 2 = 2x + 9
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x = 7
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2. -[3X-(2X+5)] = -4 -[3(2X-4)-3X]
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-(3x -(2x+5)) = -4 -(3(2x-4)-3x)
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-(3x -2x -5) = -4 -(6x -12 -3x)
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-3x +2x +5 = -4 -(3x -12)
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-x + 5 = -4 -3x + 12
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-x + 5 = -3x + 8
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2x = 3
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x = 3/2