Question 503224
For a regular polygon with n sides of length s:
Perimeter = n*s = 14
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{{{Area = 8 = ns^2*cot(180/n)}}}
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The area of a triangle (n=3) is:
s = 14/3
Area = 3*(14/3)^2*cot(60)
Area = 37.72
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Area of a square (n=4) is:
s = 14/4
Area = 4*(14/4)^2*cot(45)
Area = 49
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The area increases with the number of sides, so it's not a regular polygon.
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Try a parallelogram
Area = b*h/2 = 8
2b + 2h = 14
b+h = 7
h = 7-b
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b*h = 16
b*(7-b) = 16
7b - b^2 - 16 = 0
{{{b^2 - 7b + 16 = 0}}}
*[invoke solve_quadratic_equation 1,-7,16]
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No real solutions.
I think there's no such plane figure.
Maybe a typo.